tag:blogger.com,1999:blog-4730773743666324035.post169885131586412729..comments2023-11-16T13:20:00.273-03:00Comments on Números y algo mas...: 156 - cinco con solo dos dosClaudiohttp://www.blogger.com/profile/08887776875701773421noreply@blogger.comBlogger36125tag:blogger.com,1999:blog-4730773743666324035.post-13411969987260234342017-12-18T12:40:58.103-03:002017-12-18T12:40:58.103-03:00Como sinh(ln(2)) = 3/4, tenemos cosh(ln(sinh(ln(2)...Como sinh(ln(2)) = 3/4, tenemos cosh(ln(sinh(ln(2)))) = 25/24, luego<br />5 = raiz(4! * cosh(ln(sinh(ln(2)))))<br /><br />También podemos hacerlo con sinh(ln(3)) = 4/3.Santiago Egido Arteagahttps://www.blogger.com/profile/14137066752624247290noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-39324081207154283482017-12-18T11:12:24.776-03:002017-12-18T11:12:24.776-03:00Otros truquillos; podemos convertir un 2 en un 1,3...Otros truquillos; podemos convertir un 2 en un 1,3,4 usando:<br />1 = tan(arg cos(inverso(raiz(2))))<br />3 = cuadrado(tan(arg cos(inverso(2)))) = pi / arg cos (inverso(2))<br />4 = cuadrado(2) = pi / arg cos(inverso(raiz(2)))<br /><br />De forma que podemos conseguir 5 como 4+1, 3+2, 3!-1, raiz(4!+1), cuadrado(3)-4.<br /><br />También lo podemos sacar a partir de:<br />tanh ln 2 = 3/5<br />tanh ln 3 = 4/5<br />cosh ln 2 = 5/4<br />cosh ln 3 = 5/3<br /><br />Y hay una forma muy sucia de sacar el 5 (o cualquier otro número) usando un solo dos... y pi:<br /><br />5 = -ln( ln(raiz(raiz(raiz(raiz(raiz(pi)))))) / ln(pi) )/ln(2)<br />Santiago Egido Arteagahttps://www.blogger.com/profile/14137066752624247290noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-64609968981572397882017-12-13T12:29:16.619-03:002017-12-13T12:29:16.619-03:00cuadrado(pi/argcos(inverso(2))) - cuadrado(2)cuadrado(pi/argcos(inverso(2))) - cuadrado(2)Santiago Egido Arteagahttps://www.blogger.com/profile/14137066752624247290noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-15822531627239571522017-12-13T12:27:47.818-03:002017-12-13T12:27:47.818-03:00Como tanh(Ln(2)) es 3/5, y argcos(1/2) es pi/3...
...Como tanh(Ln(2)) es 3/5, y argcos(1/2) es pi/3...<br />pi / ( argcos(inverso(2)) * tanh(ln(2)) )Santiago Egido Arteagahttps://www.blogger.com/profile/14137066752624247290noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-48534702015986479602017-12-13T12:22:00.309-03:002017-12-13T12:22:00.309-03:00cosh(Ln(2)) * cuadrado(2)cosh(Ln(2)) * cuadrado(2)Santiago Egido Arteagahttps://www.blogger.com/profile/14137066752624247290noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-28860288350236877912017-12-13T12:03:13.567-03:002017-12-13T12:03:13.567-03:00Otra solución con un solo 2 (me parece un poco tra...Otra solución con un solo 2 (me parece un poco trampa...)<br />Ln(inverso( Ln( raiz(raiz(raiz(raiz(raiz(pi))))) )/Ln(pi) )) / Ln(2)Santiago Egido Arteagahttps://www.blogger.com/profile/14137066752624247290noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-43192438155817348812017-12-13T11:56:59.548-03:002017-12-13T11:56:59.548-03:00raiz(factorial(cuadrado(2)) + tan(arg cos(inverso(...raiz(factorial(cuadrado(2)) + tan(arg cos(inverso(raiz(2)))))Santiago Egido Arteagahttps://www.blogger.com/profile/14137066752624247290noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-16438679229060428452017-12-13T11:55:24.158-03:002017-12-13T11:55:24.158-03:00factorial(pi/arg cos(inverso(2))) - tan(arg cos(in...factorial(pi/arg cos(inverso(2))) - tan(arg cos(inverso(raiz(2))))Santiago Egido Arteagahttps://www.blogger.com/profile/14137066752624247290noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-37770202832881502572017-12-13T11:47:14.299-03:002017-12-13T11:47:14.299-03:00Si la calculadora tiene logaritmo en base dos;
-lo...Si la calculadora tiene logaritmo en base dos;<br />-logaritmobinario(logaritmobinario(raiz(raiz(raiz(raiz(raiz(2)))))))Santiago Egido Arteagahttps://www.blogger.com/profile/14137066752624247290noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-10651213243628934142017-12-13T11:41:54.238-03:002017-12-13T11:41:54.238-03:002 + pi / arg cos (inverso(2))2 + pi / arg cos (inverso(2))Santiago Egido Arteagahttps://www.blogger.com/profile/14137066752624247290noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-75040636843273503312017-12-13T11:40:23.040-03:002017-12-13T11:40:23.040-03:00cuadrado(2) + tan(arg cos(raiz(inverso(2))))cuadrado(2) + tan(arg cos(raiz(inverso(2))))Santiago Egido Arteagahttps://www.blogger.com/profile/14137066752624247290noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-90768977585713940392010-05-08T04:44:16.747-03:002010-05-08T04:44:16.747-03:00(pi x pi x pi x pi x pi)
------------------------
...(pi x pi x pi x pi x pi)<br />------------------------<br /> pi +2 -2Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-17344125803508800182009-08-10T15:14:06.929-03:002009-08-10T15:14:06.929-03:00o tambien Pi + 2 y luego int.o tambien Pi + 2 y luego int.Anonymoushttps://www.blogger.com/profile/04368197897016863517noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-23255890078306699012009-08-10T15:13:10.617-03:002009-08-10T15:13:10.617-03:00Usando la calculadora de windows
Pi + 2, paso a bi...Usando la calculadora de windows<br />Pi + 2, paso a binario y luego a decimalAnonymoushttps://www.blogger.com/profile/04368197897016863517noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-60550742269025791502009-08-05T14:19:59.563-03:002009-08-05T14:19:59.563-03:00Otra forma aproximada seria la suma de CosH(2)+ Co...Otra forma aproximada seria la suma de CosH(2)+ CosH^-1 (2) =5,07Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-59226958190599260762009-08-03T01:09:18.423-03:002009-08-03T01:09:18.423-03:00•WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••...•WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS••WEVOS•Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-65361106158915047312009-08-02T06:01:11.422-03:002009-08-02T06:01:11.422-03:00En la calculadora de windows:
2-2====NotEn la calculadora de windows:<br /><br />2-2====NotAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-83913931427038131452009-08-02T05:40:55.059-03:002009-08-02T05:40:55.059-03:00weones nerds...weones nerds...Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-63088968611767280152009-08-02T02:38:35.082-03:002009-08-02T02:38:35.082-03:00En una calculadora con funciones de edición podemo...En una calculadora con funciones de edición podemos hacer:<br /><br />2<br />Pasar a Binario = 10<br />Copiar<br />Pasar a Decimal<br />Pegar<br />/2 = 5<br /><br />":^)Jose Anoreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-63135703012103950082009-08-01T13:59:49.540-03:002009-08-01T13:59:49.540-03:002 elevado al cuadrado mas 2 elevado a la 02 elevado al cuadrado mas 2 elevado a la 0Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-87857498644100301472009-08-01T12:25:19.096-03:002009-08-01T12:25:19.096-03:00otra solucion (10^cos(log(2)))/2
sale 4.9998411 qu...otra solucion (10^cos(log(2)))/2<br />sale 4.9998411 que creo es un resultado mas que aceptable...Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-56976794726909400782009-08-01T09:18:52.940-03:002009-08-01T09:18:52.940-03:00Otra forma, sería aprovechar las teclas x^2 y 10^?...Otra forma, sería aprovechar las teclas x^2 y 10^?, me explico:<br />para la expresión 10^2^2, en realidad no utilizo nunca la tecla "2", a eso le hago una raiz de 2^2 (ahí ya he utilizado un 2) eso da 10, entre mi segundo 2...=5Unknownhttps://www.blogger.com/profile/12580719073221833426noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-79394341830326159532009-08-01T09:15:12.578-03:002009-08-01T09:15:12.578-03:00a ver, otra forma sencilla es si pones la calculad...a ver, otra forma sencilla es si pones la calculadora con "o" decimales, al hacer e^2+2=5 jijiUnknownhttps://www.blogger.com/profile/12580719073221833426noreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-75920868091061626152009-08-01T08:46:28.849-03:002009-08-01T08:46:28.849-03:00(2+2+2+2+2)/2=5(2+2+2+2+2)/2=5angelnoreply@blogger.comtag:blogger.com,1999:blog-4730773743666324035.post-76087969316416625912009-08-01T07:54:01.742-03:002009-08-01T07:54:01.742-03:00Si pulsas dos veces al más tienes una suma acumula...Si pulsas dos veces al más tienes una suma acumulada.<br /><br />2++====/2<br /><br />En mi casio y en la de windows funciona :PAnonymousnoreply@blogger.com